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Multiplication facts to 10

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5157613
Write and solve these multiplication facts. In each fact, the same number is used twice. a) \(1\times1\) b) \(2\times2\) c) \(5\times5\) d) \(10\times10\)

Hints

- Use the same number as both factors in each fact. - Recall the multiplication fact for each pair. - Check that both factors match.

Solution

1. \(1\times1=1\). 2. \(2\times2=4\). 3. \(5\times5=25\). 4. \(10\times10=100\).

Answer

a) \(1\times1=1\) b) \(2\times2=4\) c) \(5\times5=25\) d) \(10\times10=100\)
5157643
For each product, write a multiplication fact that uses the same number twice. \(16, 36, 49, 64, 81\)

Hints

- Look for a number that can be multiplied by itself to make each product. - Use the same number as both factors. - Check each multiplication fact.

Solution

1. \(4\times4=16\). 2. \(6\times6=36\). 3. \(7\times7=49\). 4. \(8\times8=64\). 5. \(9\times9=81\).

Answer

\(4 \times 4 = 16\) \(6 \times 6 = 36\) \(7 \times 7 = 49\) \(8 \times 8 = 64\) \(9 \times 9 = 81\)
5157673
Find these 6s facts. a) \(1\times6\) b) \(2\times6\) c) \(5\times6\) d) \(10\times6\)

Hints

- Start with the 1s and 2s facts. - Think about counting by \(5\)s for \(5\times6\). - Multiplying by \(10\) gives ten groups of \(6\).

Solution

1. \(1\times6=6\). 2. \(2\times6=12\). 3. \(5\times6=30\). 4. \(10\times6=60\).

Answer

a) \(1\times6=6\) b) \(2\times6=12\) c) \(5\times6=30\) d) \(10\times6=60\)
5158043
Complete the multiplication facts. a) \(8 \times 1 = \square\) b) \(1 \times 6 = \square\) c) \(9 \times 0 = \square\) d) \(0 \times 4 = \square\) What happens when you multiply a number by \(1\)? What happens when you multiply a number by \(0\)?

Hints

- Compare each product with the number that is not \(0\) or \(1\). - Look at parts a and b together. What stayed the same? - Look at parts c and d together. What do both products have in common?

Solution

1. \(8 \times 1 = 8\). 2. \(1 \times 6 = 6\). 3. \(9 \times 0 = 0\). 4. \(0 \times 4 = 0\). 5. Multiplying a number by \(1\) keeps the number the same. Multiplying a number by \(0\) gives \(0\).

Answer

a) \(8\) b) \(6\) c) \(0\) d) \(0\) Multiplying a number by \(1\) keeps the number the same. Multiplying a number by \(0\) gives \(0\).
5158053
Complete each multiplication fact. a) \(5 \times 0 = \square\) b) \(0 \times 3 = \square\) c) \(1 \times 8 = \square\) d) \(4 \times 1 = \square\) What rule do parts a and b show about multiplying by \(0\)?

Hints

- Compare the number that is not \(0\) or \(1\) with the product. - Look closely at the two facts that contain \(0\). - What do those two products have in common?

Solution

1. \(5 \times 0 = 0\). 2. \(0 \times 3 = 0\). 3. \(1 \times 8 = 8\). 4. \(4 \times 1 = 4\). 5. Multiplying any number by \(0\) gives \(0\).

Answer

a) \(0\) b) \(0\) c) \(8\) d) \(4\) Multiplying any number by \(0\) gives \(0\).
5158663
Match each product to the multiplication fact that uses the same number twice. Products: \(64\), \(36\), \(100\), \(49\) Facts: \(10\times10\), \(7\times7\), \(8\times8\), \(6\times6\)

Hints

- Each fact uses the same number twice. - Find each product. - Match equal values.

Solution

1. Find each product: \(8\times8=64\), \(6\times6=36\), \(10\times10=100\), and \(7\times7=49\). 2. Match each product to its multiplication fact.

Answer

\(64 = 8 \times 8\) \(36 = 6 \times 6\) \(100 = 10 \times 10\) \(49 = 7 \times 7\)
5179333
The numbers are \(8, 11, 16, 19, 20, 25, 28, 31, 36, 40\). Write all the numbers that are products in the 4s facts.

Hints

- Say the 4s products in order. - Check each number in the list. - Which numbers appear when you count by \(4\)s?

Solution

1. Recall the 4s products through \(4 \times 10\). 2. The listed products in the 4s facts are \(8=2 \times 4\), \(16=4 \times 4\), \(20=5 \times 4\), \(28=7 \times 4\), \(36=9 \times 4\), and \(40=10 \times 4\).

Answer

\(8, 16, 20, 28, 36, 40\)
5200183
Work out both sides, then write \(<\), \(>\), or \(=\). a) \(0 \times 6\;\square\;0 + 6\) b) \(4 \times 0 + 2\;\square\;2 \times 0 + 4\) c) \(0 \times 8 + 8\;\square\;8 \times 1 + 0\) d) \(9 \times 0\;\square\;0 \times 7\)

Hints

- Do the multiplication before addition. - Any number multiplied by \(0\) equals \(0\). - Any number multiplied by \(1\) equals that number.

Solution

1. For a), \(0 \times 6 = 0\) and \(0 + 6 = 6\), so \(0 < 6\). 2. For b), \(4 \times 0 + 2 = 2\) and \(2 \times 0 + 4 = 4\), so \(2 < 4\). 3. For c), both sides equal \(8\), so they are equal. 4. For d), both sides equal \(0\), so they are equal.

Answer

a) \(<\) b) \(<\) c) \(=\) d) \(=\)
5550813
Find each product. a) \(3 \times 7\) b) \(8 \times 4\) c) \(6 \times 9\) d) \(2 \times 8\) e) \(5 \times 6\) f) \(7 \times 7\)

Hints

- Work through the facts in any order. - If one product is hard to remember, use a multiplication fact you know well to help. - Check that each product makes sense for the two factors.

Solution

1. \(3 \times 7=21\). 2. \(8 \times 4=32\). 3. \(6 \times 9=54\). 4. \(2 \times 8=16\). 5. \(5 \times 6=30\). 6. \(7 \times 7=49\).

Answer

a) \(21\) b) \(32\) c) \(54\) d) \(16\) e) \(30\) f) \(49\)
5157583
Facts with \(1\), \(2\), \(5\), and \(10\) are often easy to use. a) Find \(1\times8\), \(2\times8\), \(5\times8\), and \(10\times8\). b) Use \(5\times8\) and \(1\times8\) to find \(6\times8\). Show your equation. c) Use \(2\times8\) to find \(4\times8\). Show how you doubled.

Hints

- Start with facts you already know well. - For part b, split \(6\) into \(5+1\). - For part c, think about how \(4\) is twice \(2\).

Solution

1. \(1\times8=8\), \(2\times8=16\), \(5\times8=40\), and \(10\times8=80\). 2. \(6\times8=(5\times8)+(1\times8)=40+8=48\). 3. Double \(2\times8=16\): \(16+16=32\), so \(4\times8=32\).

Answer

a) \(1\times8=8\), \(2\times8=16\), \(5\times8=40\), \(10\times8=80\) b) \(6\times8=(5\times8)+(1\times8)=48\) c) \(2\times8=16\), then \(16+16=32\), so \(4\times8=32\)
5157603
What number makes each multiplication fact true? a) \(7 \times \square = 35\) b) \(\square \times 9 = 18\) c) \(\square \times \square = 49\) In part c, the same number goes in both boxes.

Hints

- Think of the multiplication facts you already know. - For each part, ask what number combines with the number shown to make the given product. - In part c, look for a multiplication fact that uses the same number twice.

Solution

1. \(7 \times 5 = 35\), so the missing number in part a is \(5\). 2. \(2 \times 9 = 18\), so the missing number in part b is \(2\). 3. \(7 \times 7 = 49\), so the missing number in both boxes in part c is \(7\).

Answer

a) \(5\) b) \(2\) c) \(7\)
5157623
Lucas wants to find \(7\times8\). He knows \(5\times8\) and \(2\times8\). Show how he can use those two facts to find \(7\times8\).

Hints

- How can \(7\) be written using \(5\) and \(2\)? - Find the two easier products. - Add those products.

Solution

1. Split \(7\) into \(5+2\). 2. \(7\times8=(5\times8)+(2\times8)\). 3. \(5\times8=40\) and \(2\times8=16\). 4. \(40+16=56\), so \(7\times8=56\).

Answer

\(7\times8=(5\times8)+(2\times8)=40+16=56\)
5157653
For each product, write a multiplication fact. Use \(2\), \(5\), or \(10\) as one factor. Use a number from \(1\) through \(10\) as the other factor. a) \(14\) b) \(45\) c) \(80\) d) \(30\) e) \(25\)

Hints

- Does the ones digit suggest the 5s or 10s facts? - If the product is even, could a 2s fact work? - A product ending in \(0\) may be a 10s fact.

Solution

1. For \(14\), use the factor \(2\): \(7 \times 2 = 14\). 2. For \(45\), use the factor \(5\): \(9 \times 5 = 45\). 3. For \(80\), use the factor \(10\): \(8 \times 10 = 80\). 4. For \(30\), either \(3 \times 10 = 30\) or \(6 \times 5 = 30\) works. 5. For \(25\), use the factor \(5\): \(5 \times 5 = 25\).

Answer

a) \(7 \times 2 = 14\) b) \(9 \times 5 = 45\) c) \(8 \times 10 = 80\) d) \(3 \times 10 = 30\) or \(6 \times 5 = 30\) e) \(5 \times 5 = 25\)
5157683
Use \(5\times9\) and \(1\times9\) to find \(6\times9\). Show your steps.

Hints

- Find \(5\times9\) first. - Find \(1\times9\). - Add the two products to make \(6\) groups of \(9\).

Solution

1. Find \(5\times9=45\). 2. Find \(1\times9=9\). 3. Add the two smaller products: \(45+9=54\). 4. Therefore, \(6\times9=54\).

Answer

\(5 \times 9 = 45\) \(1 \times 9 = 9\) \(45 + 9 = 54\) \(6 \times 9 = 54\)
5157693
Complete the multiplication table. <table> <tr> <td>\(\times\)</td> <td>\(2\)</td> <td>\(5\)</td> <td>\(10\)</td> </tr> <tr> <td>\(4\)</td> <td></td> <td></td> <td></td> </tr> <tr> <td>\(7\)</td> <td></td> <td></td> <td></td> </tr> </table>

Hints

- Work one row at a time. - Multiply the row number by \(2\), \(5\), and \(10\). - Check that every box is a product of its row and column numbers.

Solution

1. For the row labeled \(4\), compute \(4 \times 2 = 8\), \(4 \times 5 = 20\), and \(4 \times 10 = 40\). 2. For the row labeled \(7\), compute \(7 \times 2 = 14\), \(7 \times 5 = 35\), and \(7 \times 10 = 70\).

Answer

Row \(4\): \(8, 20, 40\) Row \(7\): \(14, 35, 70\)
5157753
Compare the products. Write \(<\), \(>\), or \(=\) in each blank. a) \(6 \times 7 \; \square \; 5 \times 8\) b) \(4 \times 9 \; \square \; 6 \times 6\) c) \(3 \times 9 \; \square \; 4 \times 7\) d) \(8 \times 7 \; \square \; 9 \times 6\)

Hints

- Find the product on each side before comparing. - Write the two products separately if that helps you compare them. - The open side of the comparison symbol faces the greater value.

Solution

1. For part a, \(6 \times 7 = 42\) and \(5 \times 8 = 40\), so \(6 \times 7 > 5 \times 8\). 2. For part b, \(4 \times 9 = 36\) and \(6 \times 6 = 36\), so \(4 \times 9 = 6 \times 6\). 3. For part c, \(3 \times 9 = 27\) and \(4 \times 7 = 28\), so \(3 \times 9 < 4 \times 7\). 4. For part d, \(8 \times 7 = 56\) and \(9 \times 6 = 54\), so \(8 \times 7 > 9 \times 6\).

Answer

a) \(>\) b) \(=\) c) \(<\) d) \(>\)
5157763
Compare the 3s facts \(3, 6, 9, \ldots\) with the 6s facts \(6, 12, 18, \ldots\). Find three different pairs of facts that have the same product. Write each pair in this form: \((\square) \times 3 = \square\) \((\square) \times 6 = \square\)

Hints

- List the 3s products and check which also appear in the 6s facts. - To keep the product the same when the factor \(3\) becomes \(6\), what must happen to the other factor? - How are \(3\) and \(6\) related?

Solution

1. Common products in the 3s and 6s facts include \(6, 12, 18, 24\), and \(30\). 2. For product \(6\), \(2 \times 3 = 6\) and \(1 \times 6 = 6\). 3. For product \(12\), \(4 \times 3 = 12\) and \(2 \times 6 = 12\). 4. For product \(18\), \(6 \times 3 = 18\) and \(3 \times 6 = 18\). 5. Other correct pairs are possible.

Answer

One possible set is: \(2 \times 3 = 6\) and \(1 \times 6 = 6\) \(4 \times 3 = 12\) and \(2 \times 6 = 12\) \(6 \times 3 = 18\) and \(3 \times 6 = 18\)
5157913
Maya uses the 10s facts to solve 9s facts. She explains, “To find \(9 \times 7\), I first find \(10 \times 7\) and then subtract \(1 \times 7\).” Use Maya’s strategy and show your work. a) \(9 \times 4\) b) \(9 \times 8\) c) \(9 \times 6\)

Hints

- How does changing a factor from \(10\) to \(9\) change the product? - How are the 10s facts and 9s facts related? - Find the 10s product first, then subtract one group.

Solution

1. For part a, \(10 \times 4 = 40\), and \(40 - 4 = 36\). Therefore, \(9 \times 4 = 36\). 2. For part b, \(10 \times 8 = 80\), and \(80 - 8 = 72\). Therefore, \(9 \times 8 = 72\). 3. For part c, \(10 \times 6 = 60\), and \(60 - 6 = 54\). Therefore, \(9 \times 6 = 54\).

Answer

a) \(10 \times 4 - 1 \times 4 = 40 - 4 = 36\) b) \(10 \times 8 - 1 \times 8 = 80 - 8 = 72\) c) \(10 \times 6 - 1 \times 6 = 60 - 6 = 54\)
5157933
Use the given fact to find each new fact. Show the step that connects the two facts. a) You know \(10\times4=40\). Use half of \(40\) to find \(5\times4\). b) You know \(8\times3=24\). Use half of \(24\) to find \(4\times3\). c) You know \(5\times7=35\). Add one more group of \(7\) to find \(6\times7\).

Hints

- In a), \(5\) is half of \(10\). - In b), \(4\) is half of \(8\). - In c), start with \(5\) groups of \(7\) and add one more group.

Solution

1. Half of \(40\) is \(20\), so \(5\times4=20\). 2. Half of \(24\) is \(12\), so \(4\times3=12\). 3. \(5\times7=35\). Add one more \(7\): \(35+7=42\), so \(6\times7=42\).

Answer

a) \(40\div2=20\), so \(5\times4=20\) b) \(24\div2=12\), so \(4\times3=12\) c) \(35+7=42\), so \(6\times7=42\)
5158683
Use multiplication facts that have the same number twice. a) Which one has a product greater than \(10\) and less than \(20\)? b) Which two have products greater than \(30\) and less than \(50\)? Write each fact and its product.

Hints

- List multiplication facts that use the same number twice. - Compare each product with the two limits in the question. - Write both the fact and its product.

Solution

1. Around the first range, \(3\times3=9\), \(4\times4=16\), and \(5\times5=25\). Only \(16\) is greater than \(10\) and less than \(20\), so a) is \(4\times4=16\). 2. Around the second range, \(5\times5=25\), \(6\times6=36\), \(7\times7=49\), and \(8\times8=64\). The products in the range are \(36\) and \(49\).

Answer

a) \(4 \times 4 = 16\) b) \(6 \times 6 = 36\) and \(7 \times 7 = 49\)
5158693
Use each \(10\)s fact to find the related \(9\)s fact. For each part, write the \(10\)s fact, the subtraction, and the \(9\)s fact. a) Find \(9\times5\) from \(10\times5\). b) Find \(9\times9\) from \(10\times9\). c) Find \(9\times4\) from \(10\times4\).

Hints

- Find the \(10\)s fact first. - Nine groups are one group fewer than ten groups. - Subtract one group of the second factor.

Solution

1. \(10 \times 5 = 50\). Removing one group of \(5\) gives \(50 - 5 = 45\), so \(9 \times 5 = 45\). 2. \(10 \times 9 = 90\). Removing one group of \(9\) gives \(90 - 9 = 81\), so \(9 \times 9 = 81\). 3. \(10 \times 4 = 40\). Removing one group of \(4\) gives \(40 - 4 = 36\), so \(9 \times 4 = 36\).

Answer

a) \(10 \times 5 = 50\); \(50 - 5 = 45\); \(9 \times 5 = 45\) b) \(10 \times 9 = 90\); \(90 - 9 = 81\); \(9 \times 9 = 81\) c) \(10 \times 4 = 40\); \(40 - 4 = 36\); \(9 \times 4 = 36\)
5158703
Use an easier fact to find each product. Show the fact you used and how you changed it. a) \(6\times4\) b) \(9\times7\) c) \(3\times8\)

Hints

- You may use facts with \(2\), \(5\), or \(10\) as one factor. - Think about adding or removing one or more equal groups. - Show the easier fact before you give the new product.

Solution

1. For part a, use \(5 \times 4 = 20\). Add one more group of \(4\): \(20 + 4 = 24\). 2. For part b, use \(10 \times 7 = 70\). Subtract one group of \(7\): \(70 - 7 = 63\). 3. For part c, use \(2 \times 8 = 16\). Add one more group of \(8\): \(16 + 8 = 24\).

Answer

a) Use \(5\times4=20\); \(20+4=24\), so \(6\times4=24\) b) Use \(10\times7=70\); \(70-7=63\), so \(9\times7=63\) c) Use \(2\times8=16\); \(16+8=24\), so \(3\times8=24\)
5158733
Choose \(0\) or \(1\) to make each equation true. a) \(6 \times \square = 6\) b) \(9 \times \square = 0\) c) \(\square \times 7 = 0\) d) \(\square \times 8 = 8\) e) \(10 \times \square = 0\)

Hints

- Which factor leaves the other number unchanged? - Which factor always makes the product \(0\)? - Try both choices mentally and check the equation.

Solution

1. Multiplying by \(1\) leaves the other factor unchanged, and multiplying by \(0\) gives a product of \(0\). 2. The completed equations are \(6 \times 1 = 6\), \(9 \times 0 = 0\), \(0 \times 7 = 0\), \(1 \times 8 = 8\), and \(10 \times 0 = 0\).

Answer

a) \(1\) b) \(0\) c) \(0\) d) \(1\) e) \(0\)
5158743
Complete the table. <table> <tr><th>Number \(n\)</th><th>\(n \times 1\)</th><th>\(n \times 0\)</th></tr> <tr><td>\(5\)</td><td>...</td><td>...</td></tr> <tr><td>\(8\)</td><td>...</td><td>\(0\)</td></tr> <tr><td>...</td><td>\(6\)</td><td>...</td></tr> <tr><td>\(0\)</td><td>...</td><td>...</td></tr> </table>

Hints

- Work one row at a time. - In the third row, which number multiplied by \(1\) equals \(6\)? - What happens when the starting number is \(0\)?

Solution

1. For \(n=5\), \(5 \times 1 = 5\) and \(5 \times 0 = 0\). 2. For \(n=8\), \(8 \times 1 = 8\). 3. If \(n \times 1 = 6\), then \(n=6\). Therefore, \(6 \times 0 = 0\). 4. For \(n=0\), \(0 \times 1 = 0\) and \(0 \times 0 = 0\).

Answer

Row \(n=5\): \(5\), \(0\) Row \(n=8\): \(8\) Row with \(n \times 1=6\): \(n=6\), and \(n \times 0=0\) Row \(n=0\): \(0\), \(0\)
5158753
The numbers \(12\), \(18\), \(30\), and \(42\) are all products in the same times table. Which times table is it? Write the matching multiplication fact for each number.

Hints

- Look for the same factor in all four multiplication facts. - Check whether each number can be made with a 6s fact. - Write one multiplication fact for each product.

Solution

1. All four numbers are products in the 6s facts. 2. \(2\times6=12\). 3. \(3\times6=18\). 4. \(5\times6=30\). 5. \(7\times6=42\).

Answer

The 6s facts: \(2\times6=12\) \(3\times6=18\) \(5\times6=30\) \(7\times6=42\)
5158773
Find each number. a) The number is twice \(9\). b) \(\square \div 5=8\) c) The number is \(7\times7\).

Hints

- “Twice” means multiply by \(2\). - For b), work backward with multiplication. - For c), use the \(7\)s facts.

Solution

1. Twice \(9\) is \(18\). 2. If a number divided by \(5\) is \(8\), the number is \(8\times5=40\). 3. \(7\times7=49\).

Answer

a) \(18\) b) \(40\) c) \(49\)
5165433
Use each given fact to find the new fact by doubling or halving the product. Show how the product changes. a) \(3\times7=21\). Find \(6\times7\). b) \(10\times4=40\). Find \(5\times4\). c) \(4\times8=32\). Find \(8\times8\). d) \(8\times6=48\). Find \(4\times6\).

Hints

- Compare the factor that changes in each pair. - If that factor doubles, the product doubles. - If that factor is halved, the product is halved.

Solution

1. Part a: the first factor doubles from \(3\) to \(6\), so the product doubles: \(2 \times 21 = 42\). Thus \(6 \times 7 = 42\). 2. Part b: the first factor halves from \(10\) to \(5\), so the product halves: \(40 \div 2 = 20\). Thus \(5 \times 4 = 20\). 3. Part c: the first factor doubles from \(4\) to \(8\), so the product doubles: \(2 \times 32 = 64\). Thus \(8 \times 8 = 64\). 4. Part d: the first factor halves from \(8\) to \(4\), so the product halves: \(48 \div 2 = 24\). Thus \(4 \times 6 = 24\).

Answer

a) \(2 \times 21 = 42\), so \(6 \times 7 = 42\) b) \(40 \div 2 = 20\), so \(5 \times 4 = 20\) c) \(2 \times 32 = 64\), so \(8 \times 8 = 64\) d) \(48 \div 2 = 24\), so \(4 \times 6 = 24\)
5175713
Break apart the second factor. Fill in the missing number, find both smaller products, and then find the whole product. a) \(6\times7=(6\times5)+(6\times\square)\) b) \(6\times8=(6\times4)+(6\times\square)\) c) \(6\times9=(6\times5)+(6\times\square)\) d) \(6\times4=(6\times2)+(6\times\square)\)

Hints

- Look at how the second factor is split in each line. - Find the missing part first. - Then find the two smaller products and add them.

Solution

1. a) \(7=5+2\). The smaller products are \(6 \times 5=30\) and \(6 \times 2=12\), so \(6 \times 7=42\). 2. b) \(8=4+4\). The smaller products are \(24\) and \(24\), so \(6 \times 8=48\). 3. c) \(9=5+4\). The smaller products are \(30\) and \(24\), so \(6 \times 9=54\). 4. d) \(4=2+2\). The smaller products are \(12\) and \(12\), so \(6 \times 4=24\).

Answer

a) \(\square=2\); \(30+12=42\) b) \(\square=4\); \(24+24=48\) c) \(\square=4\); \(30+24=54\) d) \(\square=2\); \(12+12=24\)
5176313
Use the example to solve each multiplication fact. Break apart the second factor so that one part is \(5\). Example: \(8 \times 7 = 8 \times 5 + 8 \times 2 = 40 + 16 = 56\) a) \(8 \times 6\) b) \(8 \times 8\) c) \(8 \times 9\)

Hints

- Break the second factor into \(5\) and another number. - Use the familiar multiplication fact with \(5\) first. - Add the two smaller products.

Solution

1. Part a: Since \(6 = 5 + 1\), \(8 \times 6 = 8 \times 5 + 8 \times 1 = 40 + 8 = 48\). 2. Part b: Since \(8 = 5 + 3\), \(8 \times 8 = 8 \times 5 + 8 \times 3 = 40 + 24 = 64\). 3. Part c: Since \(9 = 5 + 4\), \(8 \times 9 = 8 \times 5 + 8 \times 4 = 40 + 32 = 72\).

Answer

a) \(8 \times 6 = 8 \times 5 + 8 \times 1 = 40 + 8 = 48\) b) \(8 \times 8 = 8 \times 5 + 8 \times 3 = 40 + 24 = 64\) c) \(8 \times 9 = 8 \times 5 + 8 \times 4 = 40 + 32 = 72\)
5176733
Use the example to solve each multiplication fact. Break apart the second factor into two addends. \(9 \times 5 = (9 \times 3) + (9 \times 2) = 27 + 18 = 45\) a) \(9 \times 4\) b) \(9 \times 7\) c) \(9 \times 8\)

Hints

- Break the second factor into two smaller numbers. - Choose multiplication facts with \(9\) that you know well. - Check that the two addends combine to make the original second factor.

Solution

1. Part a: Use \(4 = 2 + 2\). Then \(9 \times 4 = 9 \times 2 + 9 \times 2 = 18 + 18 = 36\). 2. Part b: Use \(7 = 5 + 2\). Then \(9 \times 7 = 9 \times 5 + 9 \times 2 = 45 + 18 = 63\). 3. Part c: Use \(8 = 5 + 3\). Then \(9 \times 8 = 9 \times 5 + 9 \times 3 = 45 + 27 = 72\).

Answer

a) \(9 \times 4 = (9 \times 2) + (9 \times 2) = 18 + 18 = 36\) b) \(9 \times 7 = (9 \times 5) + (9 \times 2) = 45 + 18 = 63\) c) \(9 \times 8 = (9 \times 5) + (9 \times 3) = 45 + 27 = 72\)
5176803
Combine the two smaller products as shown in the example. Example: \((5 \times 4) + (5 \times 2) = 5 \times (4 + 2) = 5 \times 6 = 30\) a) \((4 \times 3) + (4 \times 5) = 4 \times \square = \square\) b) \((7 \times 2) + (7 \times 6) = 7 \times \square = \square\) c) \((3 \times 8) + (3 \times 2) = 3 \times \square = \square\) d) \((6 \times 4) + (6 \times 4) = 6 \times \square = \square\)

Hints

- Find the factor that is the same in both smaller products. - Add the other two factors. - Multiply the common factor by that sum.

Solution

1. Part a: Add the numbers of groups: \(3 + 5 = 8\). Then \((4 \times 3) + (4 \times 5) = 4 \times 8 = 32\). 2. Part b: Add the numbers of groups: \(2 + 6 = 8\). Then \((7 \times 2) + (7 \times 6) = 7 \times 8 = 56\). 3. Part c: Add the numbers of groups: \(8 + 2 = 10\). Then \((3 \times 8) + (3 \times 2) = 3 \times 10 = 30\). 4. Part d: Add the numbers of groups: \(4 + 4 = 8\). Then \((6 \times 4) + (6 \times 4) = 6 \times 8 = 48\).

Answer

a) \(4 \times 8 = 32\) b) \(7 \times 8 = 56\) c) \(3 \times 10 = 30\) d) \(6 \times 8 = 48\)
5176813
Fill in the missing number in each line. Then find the two smaller products and the whole product. a) \((8\times3)+(8\times4)=8\times\square\) b) \((5\times7)+(5\times\square)=5\times9\) c) \((9\times6)+(9\times4)=9\times\square\) d) \((2\times\square)+(2\times3)=2\times8\)

Hints

- Look at how the second factors are being combined. - Find the missing number first. - Then find both smaller products and add them.

Solution

1. a) \(3+4=7\). The smaller products are \(24\) and \(32\), so the final product is \(56\). 2. b) \(7+2=9\). The smaller products are \(35\) and \(10\), so the final product is \(45\). 3. c) \(6+4=10\). The smaller products are \(54\) and \(36\), so the final product is \(90\). 4. d) \(5+3=8\). The smaller products are \(10\) and \(6\), so the final product is \(16\).

Answer

a) \(\square=7\); \(24+32=56\) b) \(\square=2\); \(35+10=45\) c) \(\square=10\); \(54+36=90\) d) \(\square=5\); \(10+6=16\)
5181083
You know \(8\times4=32\). Use that fact to complete each line. a) Turn the fact around: \(\square\times\square=32\) b) Add one more group of \(4\): \(9\times4=32+\square=\square\) c) Take away one group of \(8\): \(8\times3=32-\square=\square\)

Hints

- In a), switch the order of the two factors. - In b), compare \(9\times4\) with \(8\times4\). - In c), compare \(8\times3\) with \(8\times4\).

Solution

1. Switch the factors to get \(4 \times 8 = 32\). 2. For \(9 \times 4\), add one more group of \(4\): \(32 + 4 = 36\). 3. For \(8 \times 3\), subtract one group of \(8\): \(32 - 8 = 24\).

Answer

a) \(4 \times 8 = 32\) b) \(9 \times 4 = 32 + 4 = 36\) c) \(8 \times 3 = 32 - 8 = 24\)
5182723
Find each value. First combine the smaller products into one multiplication fact. Example: \((6\times4)+(6\times2)=6\times6=36\) a) \((8\times3)+(8\times7)\) b) \((5\times9)-(5\times4)\) c) \((4\times2)+(4\times2)+(4\times2)\) d) \((9\times10)-(9\times1)\)

Hints

- Find the factor that stays the same in each expression. - Add or subtract the numbers of groups. - Multiply the common factor by the number of groups you found.

Solution

1. Part a: Combine the groups: \(3 + 7 = 10\). Then \((8 \times 3) + (8 \times 7) = 8 \times 10 = 80\). 2. Part b: Subtract the groups: \(9 - 4 = 5\). Then \((5 \times 9) - (5 \times 4) = 5 \times 5 = 25\). 3. Part c: Combine all three sets of groups: \(2 + 2 + 2 = 6\). Then the expression equals \(4 \times 6 = 24\). 4. Part d: Subtract the groups: \(10 - 1 = 9\). Then \((9 \times 10) - (9 \times 1) = 9 \times 9 = 81\).

Answer

a) \(8 \times 10 = 80\) b) \(5 \times 5 = 25\) c) \(4 \times 6 = 24\) d) \(9 \times 9 = 81\)
5182873
Mia uses multiplication facts with \(5\) and \(2\) to find facts with \(7\). Show how she can solve each problem. a) \(7 \times 4\) b) \(7 \times 7\) c) \(7 \times 9\) Write your work as in this example: \(7 \times 3 = (5 \times 3) + (2 \times 3) = 15 + 6 = 21\)

Hints

- Break \(7\) into the two numbers Mia uses. - Multiply both parts by the other factor. - Add the two smaller products.

Solution

1. Part a: Break \(7\) into \(5 + 2\). Then \(7 \times 4 = 5 \times 4 + 2 \times 4 = 20 + 8 = 28\). 2. Part b: Break \(7\) into \(5 + 2\). Then \(7 \times 7 = 5 \times 7 + 2 \times 7 = 35 + 14 = 49\). 3. Part c: Break \(7\) into \(5 + 2\). Then \(7 \times 9 = 5 \times 9 + 2 \times 9 = 45 + 18 = 63\).

Answer

a) \(7 \times 4 = (5 \times 4) + (2 \times 4) = 20 + 8 = 28\) b) \(7 \times 7 = (5 \times 7) + (2 \times 7) = 35 + 14 = 49\) c) \(7 \times 9 = (5 \times 9) + (2 \times 9) = 45 + 18 = 63\)
5184163
Rewrite each expression as one multiplication fact before finding its value. a) \(4\times9+6\times9\) b) \(8\times7-3\times7\) c) \(5\times8+5\times2\) d) \(10\times6-2\times6\)

Hints

- Find the factor that is the same in the two products. - Combine the other two factors first. - Write the new multiplication fact before finding its product.

Solution

1. \(4\times9+6\times9=(4+6)\times9=10\times9=90\). 2. \(8\times7-3\times7=(8-3)\times7=5\times7=35\). 3. \(5\times8+5\times2=5\times(8+2)=5\times10=50\). 4. \(10\times6-2\times6=(10-2)\times6=8\times6=48\).

Answer

a) \(4\times9+6\times9=10\times9=90\) b) \(8\times7-3\times7=5\times7=35\) c) \(5\times8+5\times2=5\times10=50\) d) \(10\times6-2\times6=8\times6=48\)
5184883
The numbers in each group all belong to the same times table. Which times table is it? a) \(14,21,35,49\) b) \(16,24,40,64\) c) \(18,27,45,81\)

Hints

- Look for one factor that works with every number in a group. - Check the 7s, 8s, and 9s facts. - You only need to name the times table for each group.

Solution

1. Group a is from the 7s facts. 2. Group b is from the 8s facts. 3. Group c is from the 9s facts.

Answer

a) 7s b) 8s c) 9s
5203873
Each grid is split into two smaller rectangles. For each grid: 1. Write a multiplication fact for each smaller rectangle. 2. Add the two products. 3. Write the multiplication fact for the whole grid.
Figure for problem 520387

Hints

- Read the rows and columns in each smaller rectangle. - Find the product of each smaller rectangle before finding the whole. - Add the two smaller products, then write the whole multiplication fact.

Solution

1. a) Split \(6\) into \(5+1\): \((5+1) \times 7=35+7=42\). 2. b) Split \(7\) into \(5+2\): \((5+2) \times 8=40+16=56\). 3. c) Split \(8\) into \(5+3\): \((5+3) \times 9=45+27=72\).

Answer

a) \(5\times7=35\) and \(1\times7=7\); \(35+7=42\); whole: \(6\times7=42\) b) \(5\times8=40\) and \(2\times8=16\); \(40+16=56\); whole: \(7\times8=56\) c) \(5\times9=45\) and \(3\times9=27\); \(45+27=72\); whole: \(8\times9=72\)
5205423
You know that \(6 \times 8 = 48\). Use that fact to find each product without starting over. Explain briefly. a) \(8 \times 6\) b) \(7 \times 8\)

Hints

- What changed in part a? - How many groups of \(8\) are in the given fact and in part b? - Can you add one more group instead of working out the whole product again?

Solution

1. In part a, only the order of the factors changes, so \(8 \times 6 = 48\). 2. Part b has one more group of \(8\) than \(6 \times 8\), so \(48 + 8 = 56\). Therefore, \(7 \times 8 = 56\).

Answer

a) \(8\times6=48\), because changing the order of the factors does not change the product. b) \(7\times8=56\), because \(7\times8\) is one more group of \(8\) than \(6\times8\), so \(48+8=56\).
5209673
Answer each multiplication question. a) In \(9\times4=36\), what are \(9\) and \(4\) called? What is \(36\) called? b) Which is greater: \(8\times7\) or \(9\times6\)? Show your work. c) A multiplication fact has a product of \(72\). One factor is \(8\). What is the other factor?

Hints

- Recall the names of the numbers and result in a multiplication equation. - Find both products before comparing them. - Use the related division fact to find the missing factor.

Solution

1. Part a: The numbers being multiplied are factors, and the result is the product. 2. Part b: \(8 \times 7 = 56\) and \(9 \times 6 = 54\). Therefore, \(8 \times 7\) is greater. 3. Part c: Find the missing factor with \(72 \div 8 = 9\). The other factor is \(9\).

Answer

a) factors; product b) \(8 \times 7\) is greater because \(56 > 54\). c) The other factor is \(9\).
5363063
Complete this product wall. Each brick is the product of the two bricks directly below it.
Figure for problem 536306

Hints

- Multiply each neighboring pair to find the brick above. - Use multiplication facts through \(10 \times 10\).

Solution

1. The second row is \(2 \times 2 = 4\), \(2 \times 1 = 2\), and \(1 \times 3 = 3\). 2. The third row is \(4 \times 2 = 8\) and \(2 \times 3 = 6\). 3. The top brick is \(8 \times 6 = 48\).

Answer

Second row: \(4\), \(2\), \(3\) Third row: \(8\), \(6\) Top: \(48\)
5373473
A horizontal boundary divides the dot array into two equal halves. Write two different equations that show the halving.
Figure for problem 537347

Hints

- Count the rows in each half. - Express “two equal amounts” with both addition and multiplication.

Solution

1. The whole array has \(6\) rows of \(9\) dots, so \(6 \times 9 = 54\). 2. Each half covers \(3\) rows of \(9\) dots, so each half contains \(3 \times 9 = 27\) dots. 3. Two equations that show the relationship are \(6 \times 9 = 3 \times 9 + 3 \times 9\) and \(6 \times 9 = 2 \times (3 \times 9)\).

Answer

For example, \(6 \times 9 = 3 \times 9 + 3 \times 9 = 27 + 27 = 54\) and \(6 \times 9 = 2 \times 27 = 54\).
5373483
The grid is split into two rectangles. Write an equation that shows the product of each smaller rectangle and adds them to find the whole grid.
Figure for problem 537348

Hints

- Count the rows and the columns in each section. - Write one multiplication fact for the left section and one for the right section. - Add those two products to find the whole grid.

Solution

1. The left section has \(6\) rows and \(5\) columns, so it represents \(6\times5=30\). 2. The right section has \(6\) rows and \(3\) columns, so it represents \(6\times3=18\). 3. Add the two smaller products: \(6\times8=6\times5+6\times3=30+18=48\).

Answer

\(6\times8=(6\times5)+(6\times3)=30+18=48\)
5373493
Maya knows \(7 \times 7=49\) but does not know \(7 \times 8\). Use the array to explain how the unknown fact can be built from the first \(7\) columns and the added eighth column.
Figure for problem 537349

Hints

- Find the \(7\)-by-\(7\) square made by the first \(7\) columns. - Find how many squares the eighth column adds. - Start with \(7\times7=49\), then add the extra column.

Solution

1. The first \(7\) columns form a \(7\)-by-\(7\) square, so they represent \(7 \times 7=49\). 2. The added eighth column contains \(7\) unit squares. 3. Therefore, \(7 \times 8=7 \times 7+7 \times 1=49+7=56\).

Answer

The first \(7\) columns show \(7 \times 7=49\). The added eighth column adds \(7\), so \(7 \times 8=49+7=56\).
5373503
Use the array. A second array, not shown, has twice as many rows as the array and the same number of dots in each row. a) Write a multiplication equation for the array. b) Use the product from part a to find the number of dots in the second array. Show a doubling equation using that product. c) Explain why doubling the number of rows doubles the total number of dots.
Figure for problem 537350

Hints

- Read the rows and dots per row from the array. - Do not invent or count a second array; use the product you found in part a). - Think of twice as many rows as two copies of the original array.

Solution

1. The array has \(4\) rows of \(6\) dots, so \(4 \times 6 = 24\). 2. The second array has twice as many equal rows, so its total is twice \(24\): \(2 \times 24 = 48\). 3. Each original row still contains \(6\) dots. Doubling the number of equal rows makes two copies of the original \(24\)-dot array, so the total doubles.

Answer

a) \(4 \times 6 = 24\) b) \(2 \times 24 = 48\), so the second array has \(48\) dots. c) Doubling the rows makes two copies of the same \(24\)-dot array, so the total doubles.
5373763
The array shows this spring's lettuce plants. Next spring, one more row with the same number of plants will be added. a) Write the multiplication fact shown by the array. b) Add one more row to find next spring's total. c) Write the new multiplication fact.
Figure for problem 537376

Hints

- Count the rows and the plants in each row of the array. - One new row has the same number of plants as each row already shown. - Add that one row to the known total, then write the new multiplication fact.

Solution

1. The array has \(8\) rows with \(6\) plants in each row, so \(8\times6=48\). 2. One more row adds \(6\) plants: \(48+6=54\). 3. The new fact is \(9\times6=54\).

Answer

a) \(8\times6=48\) b) \(48+6=54\) c) \(9\times6=54\)
5373943
In the square array shown, every square should be filled, but one square is unfilled. a) Give the unfilled square’s row and column, counting from the top and from the left. b) Without counting the filled squares one by one, write the multiplication fact that uses the same number twice for the whole grid and the subtraction used to find the number of filled squares.
Figure for problem 537394

Hints

- Use the row and column position to locate the unfilled square. - Treat the complete grid as a multiplication fact that uses the same number twice rather than counting cells. - Subtract the number of unfilled squares from the whole-grid product.

Solution

1. The unfilled square is in row \(3\), column \(3\). 2. The grid has \(6\) rows and \(6\) columns, so the whole grid has \(6 \times 6=36\) squares. 3. One square is unfilled, so \(36-1=35\) squares are filled.

Answer

a) Row \(3\), column \(3\) b) \(6 \times 6=36\), then \(36-1=35\) filled squares
5373993
A horizontal line divides the dot array into two equal parts. Write a multiplication equation for one part and another for the whole array. Then explain how the whole product is related to the product for one part.
Figure for problem 537399

Hints

- Use the image to count the rows in the top half and the number of dots in each row. - Compare the number of rows in one half with the number in the whole array. - Say how the two products are related.

Solution

1. The top half has \(3\) rows of \(8\) dots, so one half contains \(3 \times 8 = 24\) dots. 2. The whole array has \(6\) rows of \(8\) dots, so \(6 \times 8 = 48\). 3. The whole consists of two equal halves, so \(48 = 2 \times 24\). Thus, \(6 \times 8\) is twice \(3 \times 8\).

Answer

One half: \(3 \times 8 = 24\) Whole: \(6 \times 8 = 48\) The whole product is twice the product for one half.
5550823
Find each product, then order the four expressions from least product to greatest product. \(9 \times 4\), \(7 \times 6\), \(8 \times 8\), \(3 \times 9\)

Hints

- Find all four products before ordering them. - Use multiplication facts you know well if that helps. - Order by product value, not by the size of the first factor.

Solution

1. The products are \(36\), \(42\), \(64\), and \(27\). 2. From least to greatest, \(27<36<42<64\). 3. Therefore, the expression order is \(3 \times 9\), \(9 \times 4\), \(7 \times 6\), \(8 \times 8\).

Answer

Products: \(9 \times 4=36\), \(7 \times 6=42\), \(8 \times 8=64\), \(3 \times 9=27\) Least to greatest: \(3 \times 9\), \(9 \times 4\), \(7 \times 6\), \(8 \times 8\)
5550833
Sofia wrote four multiplication facts. a) \(4 \times 8=32\) b) \(7 \times 9=56\) c) \(6 \times 6=36\) d) \(8 \times 5=45\) Which facts are incorrect? Correct each incorrect fact.

Hints

- Check all four facts. Do not assume only one is wrong. - Use multiplication facts you know well to check any fact you are unsure about. - Correct every fact that is wrong.

Solution

1. \(4 \times 8=32\) is correct. 2. \(7 \times 9\) equals \(63\), not \(56\), so b) is incorrect. 3. \(6 \times 6=36\) is correct. 4. \(8 \times 5\) equals \(40\), not \(45\), so d) is incorrect.

Answer

b) is incorrect: \(7 \times 9=63\). d) is incorrect: \(8 \times 5=40\).
5550843
Find the missing factor in each multiplication fact. a) \(7\times\square=42\) b) \(8\times\square=56\) c) \(9\times\square=54\) d) \(6\times\square=48\)

Hints

- Start with the product and the factor you already know. - Think of a multiplication fact that makes that product. - Check that each completed equation uses the given factor and product.

Solution

1. A matching fact for \(42\) with factor \(7\) is \(7 \times 6=42\). 2. A matching fact for \(56\) with factor \(8\) is \(8 \times 7=56\). 3. A matching fact for \(54\) with factor \(9\) is \(9 \times 6=54\). 4. A matching fact for \(48\) with factor \(6\) is \(6 \times 8=48\).

Answer

a) \(7 \times 6=42\) b) \(8 \times 7=56\) c) \(9 \times 6=54\) d) \(6 \times 8=48\)
5157773
Complete the table so that the two multiplication facts in each row have the same product. <table> <tr> <td>5s facts</td> <td>Product</td> <td>10s facts</td> </tr> <tr> <td>\(2 \times 5 =\)</td> <td>\(10\)</td> <td>\(\square \times 10 =\)</td> </tr> <tr> <td>\(\square \times 5 =\)</td> <td>\(20\)</td> <td>\(2 \times 10 =\)</td> </tr> <tr> <td>\(6 \times 5 =\)</td> <td>\(\square\)</td> <td>\(\square \times 10 =\)</td> </tr> <tr> <td>\(\square \times 5 =\)</td> <td>\(40\)</td> <td>\(4 \times 10 =\)</td> </tr> </table>

Hints

- Start with the product in the middle column. - How many groups of \(10\) make that product? - Once the product is known, find the missing factor in the other fact.

Solution

1. In the first row, \(1 \times 10 = 10\), so the missing factor is \(1\). 2. In the second row, \(4 \times 5 = 20\), so the missing factor is \(4\). 3. In the third row, \(6 \times 5 = 30\). The matching 10s fact is \(3 \times 10 = 30\). 4. In the fourth row, \(8 \times 5 = 40\), so the missing factor is \(8\).

Answer

Row 1: \(1 \times 10\) Row 2: \(4 \times 5\) Row 3: product \(30\); \(3 \times 10\) Row 4: \(8 \times 5\)
5157803
Max says, “There are more multiplication facts with a product of \(24\) than with a product of \(25\).” Use factors from \(1\) through \(10\). Decide whether Max is correct by listing every multiplication equation for each product.

Hints

- First list every multiplication fact you know with a product of \(24\). - Then list the multiplication facts with a product of \(25\). - Count the equations in each list and compare the totals.

Solution

1. The multiplication equations with a product of \(24\) are \(3 \times 8 = 24\), \(8 \times 3 = 24\), \(4 \times 6 = 24\), and \(6 \times 4 = 24\). There are \(4\) equations. 2. The only multiplication equation with a product of \(25\) is \(5 \times 5 = 25\). There is \(1\) equation. 3. Since \(4 > 1\), Max is correct.

Answer

Max is correct. Product of \(24\): \(3 \times 8\), \(8 \times 3\), \(4 \times 6\), \(6 \times 4\) Product of \(25\): \(5 \times 5\)
5157923
Doubling known products can help you solve other multiplication facts. a) First find \(2 \times 8\). Double that product to find \(4 \times 8\). Double the new product again to find \(8 \times 8\). b) Find \(3 \times 6\). How can you use that product to find \(6 \times 6\)? Explain and give the product.

Hints

- What happens to the product when the number of equal groups doubles? - How are the factors \(2\), \(4\), and \(8\) related? - Can repeated addition of a known product help you find the next one?

Solution

1. For part a, \(2 \times 8 = 16\). Doubling \(16\) gives \(32\), so \(4 \times 8 = 32\). Doubling \(32\) gives \(64\), so \(8 \times 8 = 64\). 2. For part b, \(3 \times 6 = 18\). Since \(6\) is twice \(3\), double \(18\) to get \(36\). Therefore, \(6 \times 6 = 36\).

Answer

a) \(2 \times 8 = 16\); \(4 \times 8 = 32\); \(8 \times 8 = 64\) b) \(6 \times 6 = 36\). Double the product \(18\) from \(3 \times 6\).
5158713
Start with each fact that uses the same number twice. Then add or subtract one equal group to find the new fact. a) \(6\times6=\square\), so \(7\times6=\square\) b) \(9\times9=\square\), so \(8\times9=\square\) c) \(5\times5=\square\), so \(4\times5=\square\) Show the addition or subtraction you used each time.

Hints

- Compare the first factor in each pair of facts. - Decide whether one equal group is being added or removed. - Show the addition or subtraction from the first product in your answer.

Solution

1. \(6 \times 6 = 36\). One more group of \(6\) gives \(36 + 6 = 42\), so \(7 \times 6 = 42\). 2. \(9 \times 9 = 81\). One fewer group of \(9\) gives \(81 - 9 = 72\), so \(8 \times 9 = 72\). 3. \(5 \times 5 = 25\). One fewer group of \(5\) gives \(25 - 5 = 20\), so \(4 \times 5 = 20\).

Answer

a) \(6 \times 6 = 36\); \(36 + 6 = 42\); \(7 \times 6 = 42\) b) \(9 \times 9 = 81\); \(81 - 9 = 72\); \(8 \times 9 = 72\) c) \(5 \times 5 = 25\); \(25 - 5 = 20\); \(4 \times 5 = 20\)
5176323
There is more than one way to break apart a multiplication fact. Complete each method for finding \(7 \times 8\). a) \(7 \times 8 = 7 \times 5 + 7 \times \dots = \dots + \dots = \dots\) b) \(7 \times 8 = 7 \times 10 - 7 \times \dots = \dots - \dots = \dots\) c) \(7 \times 8 = 7 \times 4 + 7 \times \dots = \dots + \dots = \dots\)

Hints

- Determine how \(8\) is being broken apart in each line. - In part b, compare \(8\) with \(10\). - In part c, split \(8\) into two equal addends.

Solution

1. Part a: Use \(8 = 5 + 3\). Then \(7 \times 8 = 7 \times 5 + 7 \times 3 = 35 + 21 = 56\). 2. Part b: Use \(8 = 10 - 2\). Then \(7 \times 8 = 7 \times 10 - 7 \times 2 = 70 - 14 = 56\). 3. Part c: Use \(8 = 4 + 4\). Then \(7 \times 8 = 7 \times 4 + 7 \times 4 = 28 + 28 = 56\).

Answer

a) \(7 \times 8 = 7 \times 5 + 7 \times 3 = 35 + 21 = 56\) b) \(7 \times 8 = 7 \times 10 - 7 \times 2 = 70 - 14 = 56\) c) \(7 \times 8 = 7 \times 4 + 7 \times 4 = 28 + 28 = 56\)
5176373
Fill in the blanks. First determine how many groups of \(8\) remain or are combined. a) \((8 \times 7) - (8 \times 2) = 8 \times \underline{\quad} = \underline{\quad}\) b) \((8 \times 3) + (8 \times 4) = 8 \times \underline{\quad} = \underline{\quad}\) c) \((8 \times 9) - (8 \times 5) = 8 \times \underline{\quad} = \underline{\quad}\) d) \((8 \times 2) + (8 \times \underline{\quad}) = 8 \times 10 = \underline{\quad}\)

Hints

- Pay attention to whether the groups of \(8\) are being added or subtracted. - Combine or subtract the numbers of groups before multiplying by \(8\). - In part d, find the number that must be added to \(2\) to make \(10\).

Solution

1. Part a: \(7 - 2 = 5\), so \((8 \times 7) - (8 \times 2) = 8 \times 5 = 40\). 2. Part b: \(3 + 4 = 7\), so \((8 \times 3) + (8 \times 4) = 8 \times 7 = 56\). 3. Part c: \(9 - 5 = 4\), so \((8 \times 9) - (8 \times 5) = 8 \times 4 = 32\). 4. Part d: \(2 + 8 = 10\), so the missing factor is \(8\), and \(8 \times 10 = 80\).

Answer

a) \(8 \times 5 = 40\) b) \(8 \times 7 = 56\) c) \(8 \times 4 = 32\) d) The missing factor is \(8\), and the result is \(80\).
5176743
Fill in the missing numbers to complete each multiplication strategy. a) \(6 \times 7 = (6 \times 5) + (6 \times \dots) = 30 + \dots = \dots\) b) \(8 \times 9 = (8 \times \dots) + (8 \times 4) = \dots + 32 = \dots\) c) \(7 \times 8 = (7 \times 4) + (7 \times \dots) = \dots + \dots = \dots\)

Hints

- The two parts of the second factor must add or subtract to make the original second factor. - Work out each smaller multiplication fact. - Add or subtract the smaller products as shown.

Solution

1. Part a: Since \(7 = 5 + 2\), \(6 \times 7 = 6 \times 5 + 6 \times 2 = 30 + 12 = 42\). 2. Part b: Since \(9 = 5 + 4\), \(8 \times 9 = 8 \times 5 + 8 \times 4 = 40 + 32 = 72\). 3. Part c: Since \(8 = 4 + 4\), \(7 \times 8 = 7 \times 4 + 7 \times 4 = 28 + 28 = 56\).

Answer

a) \(6 \times 7 = (6 \times 5) + (6 \times 2) = 30 + 12 = 42\) b) \(8 \times 9 = (8 \times 5) + (8 \times 4) = 40 + 32 = 72\) c) \(7 \times 8 = (7 \times 4) + (7 \times 4) = 28 + 28 = 56\)
5182883
You can break apart either factor to make a multiplication problem easier. Find two different ways to calculate \(6 \times 8\). Method 1—break apart \(6\): \((\dots \times 8) + (\dots \times 8) = \dots + \dots = \dots\) Method 2—break apart \(8\): \((6 \times \dots) + (6 \times \dots) = \dots + \dots = \dots\)

Hints

- For the first method, write \(6\) as a sum of two positive whole numbers. - For the second method, write \(8\) as a sum of two positive whole numbers. - Check that both methods give the same product.

Solution

1. For Method 1, one possible split is \(6=3+3\). Then \(6\times8=3\times8+3\times8=24+24=48\). 2. For Method 2, one possible split is \(8=4+4\). Then \(6\times8=6\times4+6\times4=24+24=48\). 3. Other correct ways to break apart \(6\) and \(8\) are also possible.

Answer

Method 1: \((3 \times 8) + (3 \times 8) = 24 + 24 = 48\) Method 2: \((6 \times 4) + (6 \times 4) = 24 + 24 = 48\) Other valid ways to break apart the factor are possible.
5183883
Each line must equal \(4\times9\). Fill in the missing number, find the two smaller products, and give the final product. a) \((4\times5)+(4\times\square)=4\times9\) b) \((4\times\square)+(4\times2)=4\times9\) c) Write a different way to break apart \(4\times9\), and solve it.

Hints

- The two smaller groups must make \(9\) groups altogether. - Find the missing part before multiplying. - In c), choose a different pair of numbers that adds to \(9\).

Solution

1. a) Since \(9=5+4\), the missing factor is \(4\). The smaller products are \(20\) and \(16\), giving \(36\). 2. b) Since \(9=7+2\), the missing factor is \(7\). The smaller products are \(28\) and \(8\), giving \(36\). 3. c) One different split is \(9=1+8\): \(4 \times 1+4 \times 8=4+32=36\). Other valid splits are possible.

Answer

a) \(\square=4\); \(20+16=36\) b) \(\square=7\); \(28+8=36\) c) For example, \((4 \times 1)+(4 \times 8)=4+32=36\).
5187123
Complete the multiplication table. First find the missing factors in the top row and first column. <table> <tr><td>\(\times\)</td><td>\(\square\)</td><td>\(7\)</td><td>\(\square\)</td></tr> <tr><td>\(2\)</td><td>\(16\)</td><td>\(\square\)</td><td>\(20\)</td></tr> <tr><td>\(\square\)</td><td>\(\square\)</td><td>\(21\)</td><td>\(\square\)</td></tr> </table>

Hints

- How can you find a missing factor when the product and one factor are known? - Use multiplication to work backward from a known product. - Complete the headers before filling the remaining products.

Solution

1. Since \(16 \div 2 = 8\), the first missing factor in the top row is \(8\). 2. Since \(20 \div 2 = 10\), the last missing factor in the top row is \(10\). 3. Since \(21 \div 7 = 3\), the missing factor in the first column is \(3\). 4. Complete the products: \(2 \times 7 = 14\), \(3 \times 8 = 24\), and \(3 \times 10 = 30\).

Answer

The completed table is: <table> <tr><td>\(\times\)</td><td>\(8\)</td><td>\(7\)</td><td>\(10\)</td></tr> <tr><td>\(2\)</td><td>\(16\)</td><td>\(14\)</td><td>\(20\)</td></tr> <tr><td>\(3\)</td><td>\(24\)</td><td>\(21\)</td><td>\(30\)</td></tr> </table>
5373013
Grid A shows the multiplication fact to find. Grid B has one extra column. Use Grid B to find the product in Grid A. Start with the \(\times10\) fact, then subtract the extra rightmost column. Show your equation and explain why it works.
Figure for problem 537301

Hints

- Compare the numbers of columns in the two images. - Find the product represented by the larger \(\times 10\) grid. - Remove exactly the rightmost column that was added.

Solution

1. Grid A has \(8\) rows and \(9\) columns. Grid B has the same \(8\) rows and \(10\) columns. 2. Grid B contains \(8 \times 10=80\) unit squares, and the added rightmost column contains \(8\) unit squares. 3. Subtract the added column: \(80-8=72\). Thus, \(8 \times 9=72\). 4. This works well because the product \(8 \times 10\) is easy to find.

Answer

\(8 \times 9=8 \times 10-8=80-8=72\). The strategy uses the easy \(\times 10\) fact and removes the added rightmost column.
5373823
The picture shows the seat arrays for Bus A and Bus B. Use \(7\times6\) to help compare them. Show: 1) \(7\times6\); 2) how to add one group to make Bus A; 3) how to add one group to make Bus B; 4) which bus has more seats and how many more.
Figure for problem 537382

Hints

- Start with \(7\times6\). - Compare each bus with that same known fact. - Show the extra group added for each bus before comparing the totals.

Solution

1. Start with \(7 \times 6=42\). 2. Bus A has one additional row of \(6\): \(42+6=48\). 3. Bus B has one additional seat in each of \(7\) rows: \(42+7=49\). 4. Therefore, Bus B has \(49-48=1\) more seat.

Answer

\(7 \times 6=42\) Bus A: \(42+6=48\) Bus B: \(42+7=49\) Bus B has \(1\) more seat.
5374003
Use \(8\times6\) to help compare \(8\times7\) and \(9\times6\). Show \(8\times6\) first. Then show one addition that makes \(8\times7\) and one addition that makes \(9\times6\). Which product is greater? How much greater?

Hints

- Start with \(8\times6\). - To make \(8\times7\), add one more group of \(8\). - To make \(9\times6\), add one more group of \(6\).

Solution

1. Start with \(8 \times 6=48\). 2. \(8 \times 7\) has one more group of \(8\), so \(48+8=56\). 3. \(9 \times 6\) has one more group of \(6\), so \(48+6=54\). 4. Therefore, \(8 \times 7\) is greater by \(56-54=2\).

Answer

\(8 \times 6=48\) \(8 \times 7=48+8=56\) \(9 \times 6=48+6=54\) \(8 \times 7\) is greater by \(2\).
5374033
Use the two grids to find \(8\times9\) in two different ways. a) Use Grid B: start with \(8\times10\) and subtract the extra column. b) Use Grid A: split it into two equal halves. Show both equations.
Figure for problem 537403

Hints

- In Grid B, compare the \(10\)-column rectangle with the \(9\)-column target. - In Grid A, split the \(8\) rows into two equal groups of \(4\). - Check that both ways give the same product.

Solution

1. Grid B shows \(8 \times 10=80\). Remove its added rightmost column of \(8\) squares: \(80-8=72\). 2. Grid A can be split into two equal groups of \(4\) rows. Each half is \(4 \times 9=36\), so \(2 \times 36=72\). 3. Both methods give \(8 \times 9=72\).

Answer

a) \(8\times9=80-8=72\) b) \(8\times9=2\times36=72\)
5503753
Use the split grid to check Eli’s equation. Eli writes \(8\times7=8\times5+2\). What is missing from Eli’s equation? Correct the equation and find the product.
Figure for problem 550375

Hints

- Look at the number of rows in both parts of the grid. - The second part needs a multiplication fact, not just its width. - Check that the two smaller products add to the whole product.

Solution

1. Both smaller rectangles have \(8\) rows. 2. The second rectangle is \(8\) rows by \(2\) columns, so it is \(8\times2\), not just \(2\). 3. The correct equation is \(8\times7=8\times5+8\times2=40+16=56\).

Answer

The missing factor is \(8\). The correct equation is \(8\times7=8\times5+8\times2=56\).
5503533
Find \(7\times9\) in two ways. Show both equations. a) Start with \(7\times10\). Explain why you subtract \(7\) to get \(7\times9\). b) Split \(7\) into \(5+2\). Use \(5\times9\) and \(2\times9\). c) Why do both ways give the same product? Which way is easier for you? Why?

Hints

- In a), compare \(9\) groups of \(7\) with \(10\) groups of \(7\). - In b), \(5+2=7\). - For c), compare what each equation is finding, not just the final number.

Solution

1. Using \(7\times10\): \(7\times10=70\). Nine groups of \(7\) are one group fewer, so \(70-7=63\). Thus \(7\times9=63\). 2. Splitting \(7\): \(7\times9=(5\times9)+(2\times9)=45+18=63\). 3. Both methods break the same \(7\times9\) product into facts we know, so both give \(63\). Either method can be easier if the learner explains why.

Answer

a) \(7\times9=70-7=63\) b) \(7\times9=(5\times9)+(2\times9)=45+18=63\) c) Both equations represent \(7\times9\), so both equal \(63\). A learner may choose either method as easier with a reasonable explanation.

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